[Mondrian] Formatters and Calculated Members in Virtual Cubes
Alan Jackson
AlanJ at symmetrics.net
Tue Mar 18 16:27:45 EDT 2008
Thanks Julian
The issue (#1407747) seems to only relate the the case where the
calculated member is in a cube
It doesn't seem to cover the case where the calculated member is in a
VIRTUAL cube.
Our calculated measure only exists in the virtual cube, it does not
exist in the physical cubes.
It looks like these work in subtly different ways.
Is it possible to have this fixed in the Virtual Cube scenario as well?
Our schema looks like:
<VirtualCube name="VirtCube">
<VirtualCubeDimension name="Dim1"/>
...
<VirtualCubeMeasure cubeName="Cube1" name="[Measures].[Measure1] />
...
<CalculatedMember dimension="Measures" forumula="..."
formatter="com.acme.myformatter" name="calcmem1" />
</VirtualCube>
Thanks
Alan
________________________________
From: mondrian-bounces at pentaho.org [mailto:mondrian-bounces at pentaho.org]
On Behalf Of Julian Hyde
Sent: 17 March 2008 23:50
To: 'Mondrian developer mailing list'
Subject: RE: [Mondrian] Formatters and Calculated Members in Virtual
Cubes
I think that was issue 1407747. See
http://sourceforge.net/tracker/index.php?func=detail&aid=1407747&group_i
d=35302&atid=414616.
Julian
________________________________
From: mondrian-bounces at pentaho.org
[mailto:mondrian-bounces at pentaho.org] On Behalf Of Alan Jackson
Sent: Monday, March 17, 2008 4:02 PM
To: mondrian at pentaho.org
Subject: [Mondrian] Formatters and Calculated Members in Virtual
Cubes
Hi Guys,
Just wondering if anyone can confirm whether this is a bug I'm
seeing or not.
If you take a Virtual Cube and add a calculated measure to it,
applying a formatter to it (FORMATTER="com.acme.myformatter") it doesn't
get applied. Applying the same formatter to a cube calculated member
works fine.
RolapVirtualCubeMeasure.java has a getFormatter method that
returns the formatter for the cube measure - should there be a check in
here for the case where the virtual cube measure doesn't have a cube
measure behind it?
TIA
Alan
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